Can you please help me you guys

ANSWER[tex]y = 3 \sin( \frac{2}{3}( x+ \frac{2}{\pi} )) - [/tex]Or[tex]y = - 3 \sin( \frac{2}{3}( x+ \frac{2}{\pi} )) - 1[/tex]EXPLANATIONThe general sine function is given by,[tex]y = a \sin(bx \pm \: c) \pm d[/tex]where[tex] |a| = 2[/tex][tex]a =\pm2[/tex][tex] \frac{2\pi}{b} = 3\pi[/tex]is the period.This implies that,[tex]b = \frac{2}{3} [/tex]The phase shift is [tex] \frac{b}{c} = \frac{\pi}{2} [/tex]This implies that,[tex]c = \frac{4}{3\pi} [/tex][tex]d = - 1[/tex]is the vertical shift.The required equation is:[tex]y = \pm3 \sin( \frac{2}{3}( x+ \frac{2}{\pi} )) - 1[/tex]