if the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions

Answer:Step-by-step explanation:if 2x^2 = 8x - 3 Move terms to the left side2x^{2}=8x-32x^{2} - (8x - 3)= 0 Distribute2x^{2}-8x+3=0Use quadratic formula x=8± √-8^2-4*2*            2*2 Simplify x=8± 2√ 10            4Separate the equations x=4- √ 10            2x=4+ √ 10            2Solve      x=4-3.2      = 0.4            2      x= 4+3.2       = 3.6            2 let me know if I'm wrong I did this mentally and i think i might have messed up somewhere but I'm like 90% this is correct